Unix commands(14)
来源:未知 责任编辑:责任编辑 发表时间:2013-11-17 14:40 点击:次
#!/bin/sh
# vim: set sw=4 ts=4 et:
help()
{
cat <
b2h -- convert binary to decimal
USAGE: b2h [-h] binarynum
OPTIONS: -h help text
EXAMPLE: b2h 111010
will return 58
HELP
exit 0
}
error()
{
# print an error and exit
echo "$1"
exit 1
}
lastchar()
{
# return the last character of a string in $rval
if [ -z "$1" ]; then
# empty string
rval=""
return
fi
# wc puts some space behind the output this is why we need sed:
numofchar=`echo -n "$1" | wc -c | sed 's/ //g' `
# now cut out the last char
rval=`echo -n "$1" | cut -b $numofchar`
}
chop()
{
# remove the last character in string and return it in $rval
if [ -z "$1" ]; then
# empty string
rval=""
return
fi
# wc puts some space behind the output this is why we need sed:
numofchar=`echo -n "$1" | wc -c | sed 's/ //g' `
if [ "$numofchar" = "1" ]; then
# only one char in string
rval=""
return
fi
numofcharminus1=`expr $numofchar "-" 1`
# now cut all but the last char:
rval=`echo -n "$1" | cut -b 0-${numofcharminus1}`
}
while [ -n "$1" ]; do
case $1 in
-h) help;shift 1;; # function help is called
--) shift;break;; # end of options
-*) error "error: no such option $1. -h for help";;
*) break;;
esac
done
# The main program
sum=0
weight=1
# one arg must be given:
[ -z "$1" ] && help
binnum="$1"
binnumorig="$1"
while [ -n "$binnum" ]; do
lastchar "$binnum"
if [ "$rval" = "1" ]; then
sum=`expr "$weight" "+" "$sum"`
fi
# remove the last position in $binnum
chop "$binnum"
binnum="$rval"
weight=`expr "$weight" "*" 2`
done
echo "binary $binnumorig is decimal $sum"
该脚本使用的算法是利用十进制和二进制数权值 (1,2,4,8,16,..),比如二进制"10"可以这样转换成十进制:
0 * 1 + 1 * 2 = 2
为了得到单个的二进制数我们是用了lastchar 函数。该函数使用wc –c计算字符个数,然后使用cut命令取出末尾一个字符。Chop函数的功能则是移除最后一个字符。
文件循环程序
或许您是想将所有发出的邮件保存到一个文件中的人们中的一员,但是在过了几个月以后,这个文件可能会变得很大以至于使对该文件的访问速度变慢。下面的 脚本rotatefile可以解决这个问题。这个脚本可以重命名邮件保存文件(假设为outmail)为outmail.1,而对于outmail.1就变成了outmail.2 等等等等...
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