oracle trunc用法
In Oracle/PLSQL, the trunc function returns a date truncated to a specific unit of measure.
The syntax for the trunc function is:
trunc ( date, [ format ] )
date is the date to truncate.
format is the unit of measure to apply for truncating. If the format parameter is omitted, the trunc function will truncate the date to the day value, so that any hours, minutes, or seconds will be truncated off.
Below are the valid format parameters:
Unit |
Valid format parameters |
Year |
SYYYY, YYYY, YEAR, SYEAR, YYY, YY, Y |
ISO Year |
IYYY, IY, I |
Quarter |
Q |
Month |
MONTH, MON, MM, RM |
Week |
WW |
IW |
IW |
W |
W |
Day |
DDD, DD, J |
Start day of the week |
DAY, DY, D |
Hour |
HH, HH12, HH24 |
Minute |
MI |
Applies To:
Oracle 8i, Oracle 9i, Oracle 10g, Oracle 11g
For example:
trunc(to_date('22-AUG-03'), 'YEAR')would return '01-JAN-03'trunc(to_date('22-AUG-03'), 'Q')would return '01-JUL-03'trunc(to_date('22-AUG-03'), 'MONTH')would return '01-AUG-03'trunc(to_date('22-AUG-03'), 'DDD')would return '22-AUG-03'trunc(to_date('22-AUG-03'), 'DAY')would return '17-AUG-03'--Oracle trunc()函数的用法
/**************日期********************/
1.select trunc(sysdate) from dual --2011-3-18 今天的日期为2011-3-18
2.select trunc(sysdate, 'mm') from dual --2011-3-1 返回当月第一天.
3.select trunc(sysdate,'yy') from dual --2011-1-1 返回当年第一天
4.select trunc(sysdate,'dd') from dual --2011-3-18 返回当前年月日
5.select trunc(sysdate,'yyyy') from dual --2011-1-1 返回当年第一天
6.select trunc(sysdate,'d') from dual --2011-3-13 (星期天)返回当前星期的第一天
7.select trunc(sysdate, 'hh') from dual --2011-3-18 14:00:00 当前时间为14:41
8.select trunc(sysdate, 'mi') from dual --2011-3-18 14:41:00 TRUNC()函数没有秒的精确
/***************数字********************/
/*
TRUNC(number,num_digits)
Number 需要截尾取整的数字。
Num_digits 用于指定取整精度的数字。Num_digits 的默认值为 0。
TRUNC()函数截取时不进行四舍五入
*/
9.select trunc(123.458) from dual --123
10.select trunc(123.458,0) from dual --123
11.select trunc(123.458,1) from dual --123.4
12.s
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