SqlServer存储过程/函数加/解密

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存储过程、存储函数的加密:WITH ENCRYPTION

<!--[if !supportLineBreakNewLine]-->
<!--[endif]-->

CREATE procedure dbo.sp_XML_main

@table_name nvarchar(260)=,

@dirname nvarchar(20)=

WITH ENCRYPTION

as

begin

....................

end

go

 

  存储过程、存储函数的解密(以下是一位绝世高人编写的代码)

 

if exists (select * from dbo.sysobjects where id = object_id(N[dbo].[sp_decrypt]) and OBJECTPROPERTY(id, NIsProcedure) = 1)

drop procedure [dbo].[sp_decrypt]

GO

/*--破解函数,过程,触发器,视图.仅限于SQLSERVER2000

--作者:J9988-- All rights reserved*/

/*--调用示例

--解密指定存储过程

exec sp_decrypt AppSP_test

--对所有的存储过程解密

declare tb cursor for

select name from sysobjects where xtype=P and status>0 and name<>sp_decrypt


declare @name sysname

open tb

fetch next from tb into @name

while @@fetch_status=0

begin

print /*-------存储过程 [+@name+] -----------*/

exec sp_decrypt @name

fetch next from tb into @name

end

close tb

deallocate tb

--*/


if exists (select * from dbo.sysobjects where id = object_id(N[dbo].[SP_DECRYPT]) and OBJECTPROPERTY(id, NIsProcedure) = 1)

drop procedure [dbo].[SP_DECRYPT]

GO

CREATE PROCEDURE sp_decrypt(@objectName varchar(50))

AS

begin

set nocount on

--破解字节不受限制,适用于SQLSERVER2000存储过程,函数,视图,触发器

--修正上一版视图触发器不能正确解密错误

begin tran

declare @objectname1 varchar(100),@orgvarbin varbinary(8000)

declare @sql1 nvarchar(4000),@sql2 varchar(8000),@sql3 nvarchar(4000),@sql4 nvarchar(4000)

DECLARE @OrigSpText1 nvarchar(4000), @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000)

declare @i int,@status int,@type varchar(10),@parentid int

declare @colid int,@n int,@q int,@j int,@k int,@encrypted int,@number int

select @type=xtype,@parentid=parent_obj from sysobjects where id=object_id(@ObjectName)

 

create table #temp(number int,colid int,ctext varbinary(8000),encrypted int,status int)

insert #temp SELECT number,colid,ctext,encrypted,status FROM syscomments WHERE id = object_id(@objectName)

select @number=max(number) from #temp

set @k=0

 

while @k<=@number

begin

if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k)

begin

if @type=P

set @sql1=(case when @number>1 then ALTER PROCEDURE + @objectName +;+rtrim(@k)+ WITH ENCRYPTION AS

else ALTER PROCEDURE + @objectName+ WITH ENCRYPTION AS

end)

 

if @type=TR

begin

declare @parent_obj varchar(255),@tr_parent_xtype varchar(10)

select @parent_obj=parent_obj from sysobjects where id=object_id(@objectName)

select @tr_parent_xtype=xtype from sysobjects where id=@parent_obj

if @tr_parent_xtype=V

begin

set @sql1=ALTER TRIGGER +@objectname+ ON +OBJECT_NAME(@parentid)+ WITH ENCRYPTION INSTERD OF INSERT AS PRINT 1

end

else

begin

set @sql1=ALTER TRIGGER +@objectname+ ON +OBJECT_NAME(@parentid)+ WITH ENCRYPTION FOR INSERT AS PRINT 1

end

 

end

if @type=FN or @type=TF or @type=IF

set @sql1=(case @type when TF then

ALTER FUNCTION + @objectName+(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end

when FN then

ALTER FUNCTION + @objectName+(@a char(1)) returns char(1) with encryption as begin return @a end

when IF then

ALTER FUNCTION + @objectName+(@a char(1)) returns table with encryption as return select @a as a

end)

 

if @type=V

set @sql1=ALTER VIEW +@objectname+ WITH ENCRYPTION AS SELECT 1 as f

 

set @q=len(@sql

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