ASP文件上传工具(只能上传一定大小文件)
来源:未知 责任编辑:责任编辑 发表时间:2013-12-18 11:34 点击:次
<%@LANGUAGE="VBSCRIPT" CODEPAGE="936"%>
<%
Response.Buffer = True
Server.ScriptTimeOut=9999999
On Error Resume Next
%>
<head> www.2cto.com
<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />
<meta http-equiv="Content-Language" content="zh-cn" />
<meta name="description" content="ASP文件上传工具" />
<style type="text/css">
<!--
body,input {font-size:12px;}
-->
</style>
<title>ASP文件上传工具</title>
</head>
<body id="body">
<%
upurl=Request.ServerVariables("URL")
ExtName = "jpg,gif,png,txt,rar,zip,doc,pdf" '允许扩展名
SavePath = "upload" '保存路径
If Right(SavePath,1)<>"/" Then SavePath=SavePath&"/" '在目录后加(/)
CheckAndCreateFolder(SavePath)
UpLoadAll_a = Request.TotalBytes '取得客户端全部内容
If(UpLoadAll_a>0) Then
Set UploadStream_c = Server.CreateObject("ADODB.Stream")
UploadStream_c.Type = 1
UploadStream_c.Open
UploadStream_c.Write Request.BinaryRead(UpLoadAll_a)
UploadStream_c.Position = 0
FormDataAll_d = UploadStream_c.Read
CrLf_e = chrB(13)&chrB(10)
FormStart_f = InStrB(FormDataAll_d,CrLf_e)
FormEnd_g = InStrB(FormStart_f+1,FormDataAll_d,CrLf_e)
Set FormStream_h = Server.Createobject("ADODB.Stream")
FormStream_h.Type = 1
FormStream_h.Open
UploadStream_c.Position = FormStart_f + 1
UploadStream_c.CopyTo FormStream_h,FormEnd_g-FormStart_f-3
FormStream_h.Position = 0
FormStream_h.Type = 2
FormStream_h.CharSet = "GB2312"
FormStreamText_i = FormStream_h.Readtext
FormStream_h.Close
FileName_j = Mid(FormStreamText_i,InstrRev(FormStreamText_i,"\")+1,FormEnd_g)
If(CheckFileExt(FileName_j,ExtName)) Then
SaveFile = Server.MapPath(SavePath & FileName_j)
If Err Then
Response.Write "文件上传: <span style=""color:red;"">文件上传出错!</span> <a href=""" & upurl&""">重新上传文件</a><br />"
<%
Response.Buffer = True
Server.ScriptTimeOut=9999999
On Error Resume Next
%>
<head> www.2cto.com
<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />
<meta http-equiv="Content-Language" content="zh-cn" />
<meta name="description" content="ASP文件上传工具" />
<style type="text/css">
<!--
body,input {font-size:12px;}
-->
</style>
<title>ASP文件上传工具</title>
</head>
<body id="body">
<%
upurl=Request.ServerVariables("URL")
ExtName = "jpg,gif,png,txt,rar,zip,doc,pdf" '允许扩展名
SavePath = "upload" '保存路径
If Right(SavePath,1)<>"/" Then SavePath=SavePath&"/" '在目录后加(/)
CheckAndCreateFolder(SavePath)
UpLoadAll_a = Request.TotalBytes '取得客户端全部内容
If(UpLoadAll_a>0) Then
Set UploadStream_c = Server.CreateObject("ADODB.Stream")
UploadStream_c.Type = 1
UploadStream_c.Open
UploadStream_c.Write Request.BinaryRead(UpLoadAll_a)
UploadStream_c.Position = 0
FormDataAll_d = UploadStream_c.Read
CrLf_e = chrB(13)&chrB(10)
FormStart_f = InStrB(FormDataAll_d,CrLf_e)
FormEnd_g = InStrB(FormStart_f+1,FormDataAll_d,CrLf_e)
Set FormStream_h = Server.Createobject("ADODB.Stream")
FormStream_h.Type = 1
FormStream_h.Open
UploadStream_c.Position = FormStart_f + 1
UploadStream_c.CopyTo FormStream_h,FormEnd_g-FormStart_f-3
FormStream_h.Position = 0
FormStream_h.Type = 2
FormStream_h.CharSet = "GB2312"
FormStreamText_i = FormStream_h.Readtext
FormStream_h.Close
FileName_j = Mid(FormStreamText_i,InstrRev(FormStreamText_i,"\")+1,FormEnd_g)
If(CheckFileExt(FileName_j,ExtName)) Then
SaveFile = Server.MapPath(SavePath & FileName_j)
If Err Then
Response.Write "文件上传: <span style=""color:red;"">文件上传出错!</span> <a href=""" & upurl&""">重新上传文件</a><br />"
相关新闻>>
最新推荐更多>>>
- 发表评论
-
- 最新评论 更多>>