android中解析服务器发过来的JSON数据

解析ＪＳＯＮ的效率要比ｘｍｌ高很多，建议在开发中，数据不是很复杂就用ＪＳＯＮ传输数据

public class VideoService { 

    public List<Video> getJsonVieos() throws IOException, JSONException{ 

        String path = "http://111.14.19.37:8080/vidoe/video/list.do?format=json"; 

        URL url = new URL(path); 

        HttpURLConnection conn = (HttpURLConnection) url.openConnection(); 

        conn.setConnectTimeout(5 * 1000); 

        conn.setRequestMethod("GET"); 

        InputStream is = conn.getInputStream(); 

        byte[] data = InputStreamUtil.getByteArray(is);／／用自己写的工具类把流转成ｂｙｔｅ数组 

        String json = new String(data); 

        JSONArray array = new JSONArray(json); 

        List<Video> videos = new ArrayList<Video>(); 

        for(int i = 0; i<array.length(); i++){ 

            JSONObject jo = array.getJSONObject(i); 

            int id = jo.getInt("id"); 

            String title = jo.getString("title"); 

            int timelength = jo.getInt("timelength"); 

            videos.add(new Video(id, title, timelength)); 

        } 

        return videos; 

    } 

}   

摘自：com360 博客